Optimal. Leaf size=100 \[ \frac{4 b^3 \sin (e+f x)}{3 f \sqrt{b \sec (e+f x)}}-\frac{8 b^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right ) \sqrt{b \sec (e+f x)}}{3 f}+\frac{2 b \sin ^3(e+f x) (b \sec (e+f x))^{3/2}}{3 f} \]
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Rubi [A] time = 0.103034, antiderivative size = 100, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {2624, 2627, 3771, 2641} \[ \frac{4 b^3 \sin (e+f x)}{3 f \sqrt{b \sec (e+f x)}}-\frac{8 b^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right ) \sqrt{b \sec (e+f x)}}{3 f}+\frac{2 b \sin ^3(e+f x) (b \sec (e+f x))^{3/2}}{3 f} \]
Antiderivative was successfully verified.
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Rule 2624
Rule 2627
Rule 3771
Rule 2641
Rubi steps
\begin{align*} \int (b \sec (e+f x))^{5/2} \sin ^4(e+f x) \, dx &=\frac{2 b (b \sec (e+f x))^{3/2} \sin ^3(e+f x)}{3 f}-\left (2 b^2\right ) \int \sqrt{b \sec (e+f x)} \sin ^2(e+f x) \, dx\\ &=\frac{4 b^3 \sin (e+f x)}{3 f \sqrt{b \sec (e+f x)}}+\frac{2 b (b \sec (e+f x))^{3/2} \sin ^3(e+f x)}{3 f}-\frac{1}{3} \left (4 b^2\right ) \int \sqrt{b \sec (e+f x)} \, dx\\ &=\frac{4 b^3 \sin (e+f x)}{3 f \sqrt{b \sec (e+f x)}}+\frac{2 b (b \sec (e+f x))^{3/2} \sin ^3(e+f x)}{3 f}-\frac{1}{3} \left (4 b^2 \sqrt{\cos (e+f x)} \sqrt{b \sec (e+f x)}\right ) \int \frac{1}{\sqrt{\cos (e+f x)}} \, dx\\ &=-\frac{8 b^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right ) \sqrt{b \sec (e+f x)}}{3 f}+\frac{4 b^3 \sin (e+f x)}{3 f \sqrt{b \sec (e+f x)}}+\frac{2 b (b \sec (e+f x))^{3/2} \sin ^3(e+f x)}{3 f}\\ \end{align*}
Mathematica [A] time = 0.134093, size = 64, normalized size = 0.64 \[ -\frac{b^2 \sqrt{b \sec (e+f x)} \left (-\sin (2 (e+f x))-2 \tan (e+f x)+8 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right )\right )}{3 f} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.14, size = 144, normalized size = 1.4 \begin{align*}{\frac{ \left ( -2+2\,\cos \left ( fx+e \right ) \right ) \cos \left ( fx+e \right ) \left ( \cos \left ( fx+e \right ) +1 \right ) ^{2}}{3\,f \left ( \sin \left ( fx+e \right ) \right ) ^{3}} \left ( 4\,i\cos \left ( fx+e \right ){\it EllipticF} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},i \right ) \sqrt{ \left ( \cos \left ( fx+e \right ) +1 \right ) ^{-1}}\sqrt{{\frac{\cos \left ( fx+e \right ) }{\cos \left ( fx+e \right ) +1}}}\sin \left ( fx+e \right ) + \left ( \cos \left ( fx+e \right ) \right ) ^{3}- \left ( \cos \left ( fx+e \right ) \right ) ^{2}+\cos \left ( fx+e \right ) -1 \right ) \left ({\frac{b}{\cos \left ( fx+e \right ) }} \right ) ^{{\frac{5}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b \sec \left (f x + e\right )\right )^{\frac{5}{2}} \sin \left (f x + e\right )^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b^{2} \cos \left (f x + e\right )^{4} - 2 \, b^{2} \cos \left (f x + e\right )^{2} + b^{2}\right )} \sqrt{b \sec \left (f x + e\right )} \sec \left (f x + e\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b \sec \left (f x + e\right )\right )^{\frac{5}{2}} \sin \left (f x + e\right )^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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